Here is a very basic implementation of OISC:2, written in Python.
Please feel free to play with it, but leave the attribution header.
Improved code with examples and a ReadMe can be found on GitHub.
# OISC2 without file reading or coprocessor.
# This is based on an implementation of Subleq found here:
# https://rosettacode.org/wiki/Subleq#Python
# It has very limited error testing. Buyer beware.
# McChuck, April 15, 2022
import sys
def oisc2(mem, negmem):
negmem = [0,2,0,0,0,0,0]+negmem
# IP, Next, Return, Reg a, Reg b, Reg c, Mode
IP = -1
NEXT = -2
RET = -3
negmem.reverse()
mem=mem+negmem
try:
while mem[IP] >= 0:
a=mem[mem[IP]]
b=mem[mem[IP]+1]
mem[NEXT]=mem[IP]+2
if a>0:
if b>0:
mem[b]-=mem[a]
elif b==0:
print(chr(mem[a]), end="")
else:
if mem[a]<=0:
mem[RET]=mem[NEXT]
mem[NEXT]=abs(b)
elif a==0:
if b>0:
mem[b]=ord(sys.stdin.read(1))
elif b==0:
mem[NEXT]=-1
else:
mem[mem[abs(b)]]=ord(sys.stdin.read(1))
else:
if b>0:
if mem[mem[abs(a)]]<=0:
mem[RET]=mem[NEXT]
mem[NEXT]=b
elif b==0:
print(chr(mem[mem[abs(a)]]), end="")
else:
mem[mem[abs(b)]]-=mem[mem[abs(a)]]
mem[IP] = mem[NEXT]
print("\nOISC2 completed successfully.")
except (ValueError, IndexError, KeyboardInterrupt):
print("OISC2 aborted at: ", ip)
print("A: ", a, "B: ", b)
print(mem)
finally:
print("\nFinished.")
oisc2([12, 12, 14, -30, 14, 0, 13, 2, 13, 4, 12, -2,
0, -1, 72, 101, 108, 108, 111, 44, 32, 119, 111, 114, 108, 100, 33, 10, 0, 14,
-29, 38, -29, 0, -40, -41, -40, 30, 0, 0, 13, 29], [0,0,1,2,3,4,5,6,0,0])
# 0 Z, Z # You can't jump back to 0, so have to pad the beginning.
# 2 Start: L, -Cont
# 4 L, 0 # Print "Hello, world!" directly
# 6 M1, Start
# 8 M1, Start+2
# 10 Z, -Start
# 12 Z: 0 .
# 13 M1: -1 .
# 14 L: "Hello, world!\n"
# 29 LP: L .
# 30 Cont: -LP Halt
# 32 -LP 0 # Now print it again, but indirectly
# 34 -M1P -LPP
# 36 -M1P Cont
# 38 Halt: 0 0
# 40 M1P: M1 .
# 41 LPP: LP .
